Thankyou TS-LABS i understand the first part but this bit has still got me puzzled.
LD A,#52 ;#52 = 0101 0010b
0 - no matter in this case
1 - RAM should be exposed to the window, else 0 - ROM
010010 - is the inversion of 101101, that means decimal 45, so:
page 45 of RAM will be shown at bank 3 (#C000)
Doesnt #52 = 0101 0010b
Because i thought 0101 0010b = 82 ?
Or am i going wrong somewhere ?
Hey i nearly have i'll be bank switching and changing video modes in no time
Thanx in advance